Math 12AP – Reviewing for the Quadratics Section of the Provincial Exam

 

The Equations!

 

General Form

Transformational Form

Standard Form

c = y-intercept

a = stretch                                

  • if a > 0 then opens up
  • if a < 0 then opens down

 ...the horiz. translation

a = stretch                               

k = vertical translation            

h = horizontal translation        

Vertex:  (h, k)

Axis of Symmetry: x = h

 

Sequences

Things to Know - Arithmetic Sequence (tn = d (n - 1) + t1), Quadratic Sequence, and Power Sequence (p.11 #30).  Common Difference, infinite Sequence, and finite sequence.

Type of Sequence

When Common

Degree

Equation

Linear  

D1 is constant

1

tn= an + b   or    tn= t1 + d(n-1)  

Quadratic

D2 is constant

2

tn= an2 + bn + c

Cubic   

D3 is constant

3

tn= an3 + bn2 + cn + d

Quartic

D4 is constant

4

tn= an4 + bn3 + cn2 + dn +e

Quintic

D5 is constant

5

tn= an5 + bn4 + cn3 + dn2 +en + f

Geometric Common Ratio n tn = t1(r)(n-1)

 

           

Completing the Square and Transformational Form

A procedure called “completing the square” is used to change from general to transformational form of an equation.

Step 1:  Move the constant at the end to the other side of the equation.

Example:

Step 2:  Divide everything by the coefficient of the x2-term.

Step 3: Take half the coefficient of the x-term and square it.  Add this square to both sides of the equation

Step 4: Factor the right side of the equation into a perfect square

Step 5: Factor out the coefficient of the y-term to get the stretch and horizontal translation.

 

The Quadratic Formula and Decomposition

-The quadratic formula can be used to find the “roots” or x-intercepts of a parabola.  This is where the curve crosses the x-axis and y is equal to zero.  There are three ways to find the roots of an equation.  The simplest way is to factor the equation, set it equal to zero and solve for x.  If the function does not factor easily, you may try factoring using decomposition.  If it really looks nasty, dive right into the quadratic formula.

 

Finding Roots using Decomposition Example

Step 1: Multiply the coefficients of the first and last term together.  Find factors of this product that add to the coefficient of the middle term.

Product of first and last term: (2)(-6) = -12

Factors: (-1, 12), (1, -12), (-2, 6), (2, -6) (-3, 4) and (3, -4)

Step 2: Split the middle term into the two factors you found in the last step

Step 3: Group the first and last two terms together

Step 4: Factor out of the groups

Step 5: Factor the common term out of each group

Step 6: Set each factor equal to zero to solve for x

 

The Quadratic Formula:             when

 

Finding Roots with the Quadratic Formula Example

Step 1: let y = 0

Step 2: Enter a, b and c coefficients into the Quadratic Formula

Step 3: Simplify

Step 4: Solve for x

 and

 

 

What a Function’s Roots Tell you about Its Graph - A quadratic function has two roots and you can find out what type of roots they are by using the discriminant.  The discriminant is the  part of the quadratic formula.

 

A Quadratic function with...

 

two real roots

a double root (two roots of the same value)

two non-real roots

has a discriminant...

positive discriminant

zero discriminant

negative discriminant

looks like this ...

and has this many x-intercepts

two x-intercepts

one x-intercept.  I call this one a “skimmer” because it just touches the x-axis and then flies away

zero x-intercepts

 

 

 

Finding the Formula of a Parabola

If you are given the vertex of a parabola and any other point on the curve, you can determine the formula for the parabola using the transformation for of the quadratic.  The vertex is (h, k) and the other point is (x, y).  When you plug the numbers into the equation, you can solve for a (the stretch).