Deriving the Quadratic Formula
Ever wanted
to dazzle your friends by deriving the quadratic formula for them? Now you can!
Just follow these simple steps and your friends will soon be in awe of
your wicked algebraic skillz.
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Start
with the general form of the quadratic function and let y = 0. |
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Subtract
c from both sides |
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Factor
out the stretch (the “a” coefficient) |
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Complete
the Square and factor it. |
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Simplify
the left side of the equation. Find a
common denominator and group the terms together. |
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Move the
stretch to the right side of the equation.
(Divide both sides by a). |
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Take the
square root of both sides of the equation. |
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Subtract
the b/2a from both sides. |
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Group
like terms and you’re there! |
From General to Transformational
Form… Deriving h
= -b/2a
Today we showed in class that the x-coordinate of the vertex of a quadratic function in general form is given by -b/2a. (p48 #26). Below is a proof of why this is always true. Just complete the square to change general form into transformational form.
|
|
Start
with the general form of the quadratic function. |
|
|
Subtract
c from both sides |
|
|
Factor
out the stretch (the “a” coefficient) |
|
|
Complete
the Square and factor it. |
|
|
Simplify
the left side of the equation. Find a
common denominator and group the terms together. |
|
|
Move the
stretch to the right side of the equation.
(Divide both sides by a). |
|
Vertex |
We can
use transformational form now to find the vertex. h = -b/2a |